16(2x-1)=4(x+3)=2x

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Solution for 16(2x-1)=4(x+3)=2x equation: 



16(2x-1)=4(x+3)=2x

We move all terms to the left:

16(2x-1)-(4(x+3))=0

We multiply parentheses

32x-(4(x+3))-16=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

32x-4x-12-16=0

We add all the numbers together, and all the variables

28x-28=0

We move all terms containing x to the left, all other terms to the right

28x=28

x=28/28

x=1

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