16(2x-7)=4(6x+1)

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Solution for 16(2x-7)=4(6x+1) equation:



16(2x-7)=4(6x+1)
We move all terms to the left:
16(2x-7)-(4(6x+1))=0
We multiply parentheses
32x-(4(6x+1))-112=0
We calculate terms in parentheses: -(4(6x+1)), so:
4(6x+1)
We multiply parentheses
24x+4
Back to the equation:
-(24x+4)
We get rid of parentheses
32x-24x-4-112=0
We add all the numbers together, and all the variables
8x-116=0
We move all terms containing x to the left, all other terms to the right
8x=116
x=116/8
x=14+1/2

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