16(3x+5)-10(4x-8)=40

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Solution for 16(3x+5)-10(4x-8)=40 equation: 



16(3x+5)-10(4x-8)=40

We move all terms to the left:

16(3x+5)-10(4x-8)-(40)=0

We multiply parentheses

48x-40x+80+80-40=0

We add all the numbers together, and all the variables

8x+120=0

We move all terms containing x to the left, all other terms to the right

8x=-120

x=-120/8

x=-15

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