16(3x-4)=32

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Solution for 16(3x-4)=32 equation: 



16(3x-4)=32

We move all terms to the left:

16(3x-4)-(32)=0

We multiply parentheses

48x-64-32=0

We add all the numbers together, and all the variables

48x-96=0

We move all terms containing x to the left, all other terms to the right

48x=96

x=96/48

x=2

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