16(3x-5)-10(4x-8)=40

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Solution for 16(3x-5)-10(4x-8)=40 equation:


Simplifying
16(3x + -5) + -10(4x + -8) = 40

Reorder the terms:
16(-5 + 3x) + -10(4x + -8) = 40
(-5 * 16 + 3x * 16) + -10(4x + -8) = 40
(-80 + 48x) + -10(4x + -8) = 40

Reorder the terms:
-80 + 48x + -10(-8 + 4x) = 40
-80 + 48x + (-8 * -10 + 4x * -10) = 40
-80 + 48x + (80 + -40x) = 40

Reorder the terms:
-80 + 80 + 48x + -40x = 40

Combine like terms: -80 + 80 = 0
0 + 48x + -40x = 40
48x + -40x = 40

Combine like terms: 48x + -40x = 8x
8x = 40

Solving
8x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '8'.
x = 5

Simplifying
x = 5

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