16(3x-5)-10(4x-8)=400

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Solution for 16(3x-5)-10(4x-8)=400 equation: 



16(3x-5)-10(4x-8)=400

We move all terms to the left:

16(3x-5)-10(4x-8)-(400)=0

We multiply parentheses

48x-40x-80+80-400=0

We add all the numbers together, and all the variables

8x-400=0

We move all terms containing x to the left, all other terms to the right

8x=400

x=400/8

x=50

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