16(3x-5)-103(4x-8)=40

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Solution for 16(3x-5)-103(4x-8)=40 equation: 



16(3x-5)-103(4x-8)=40

We move all terms to the left:

16(3x-5)-103(4x-8)-(40)=0

We multiply parentheses

48x-412x-80+824-40=0

We add all the numbers together, and all the variables

-364x+704=0

We move all terms containing x to the left, all other terms to the right

-364x=-704

x=-704/-364

x=1+85/91

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