16(3y-5)-10(4y-8)=40

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Solution for 16(3y-5)-10(4y-8)=40 equation: 



16(3y-5)-10(4y-8)=40

We move all terms to the left:

16(3y-5)-10(4y-8)-(40)=0

We multiply parentheses

48y-40y-80+80-40=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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