16(4-3m)=96(-(m/2)+1)

Solution for 16(4-3m)=96(-(m/2)+1) equation:

16(4-3m)=96(-(m/2)+1)

We move all terms to the left:

16(4-3m)-(96(-(m/2)+1))=0

We add all the numbers together, and all the variables

16(-3m+4)-(96(-(+m/2)+1))=0

We multiply parentheses

-48m-(96(-(+m/2)+1))+64=0

We multiply all the terms by the denominator


-48m*2)+1))-(96(-(+m+64*2)+1))=0

We add all the numbers together, and all the variables

-48m*2)+1))-(96(-(m+128)+1))=0

We add all the numbers together, and all the variables

-48m*2)+1))-(96(-(m=0

Wy multiply elements

-96m^2=0

a = -96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-96)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-192}=0$