16(4-3x)=96(-x/2)

Solution for 16(4-3x)=96(-x/2) equation:

16(4-3x)=96(-x/2)

We move all terms to the left:

16(4-3x)-(96(-x/2))=0

We add all the numbers together, and all the variables

16(-3x+4)-(96(-x/2))=0

We multiply parentheses

-48x-(96(-x/2))+64=0

We multiply all the terms by the denominator


-48x*2))-(96(-x+64*2))=0

We add all the numbers together, and all the variables

-48x*2))-(96(-1x+128))=0

We add all the numbers together, and all the variables

-1x-48x*2))-(96(=0

Wy multiply elements

-96x^2-1x=0

a = -96; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-96)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-96}=\frac{0}{-192}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-96}=\frac{2}{-192}
=-1/96
$