16(4x+1)+7x+9(x-3)=4

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Solution for 16(4x+1)+7x+9(x-3)=4 equation: 



16(4x+1)+7x+9(x-3)=4

We move all terms to the left:

16(4x+1)+7x+9(x-3)-(4)=0

We add all the numbers together, and all the variables

7x+16(4x+1)+9(x-3)-4=0

We multiply parentheses

7x+64x+9x+16-27-4=0

We add all the numbers together, and all the variables

80x-15=0

We move all terms containing x to the left, all other terms to the right

80x=15

x=15/80

x=3/16

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