16(b+11)=3(b+1)

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Solution for 16(b+11)=3(b+1) equation: 



16(b+11)=3(b+1)

We move all terms to the left:

16(b+11)-(3(b+1))=0

We multiply parentheses

16b-(3(b+1))+176=0



We calculate terms in parentheses: -(3(b+1)), so:

3(b+1)

We multiply parentheses

3b+3

Back to the equation:

-(3b+3)



We get rid of parentheses

16b-3b-3+176=0

We add all the numbers together, and all the variables

13b+173=0

We move all terms containing b to the left, all other terms to the right

13b=-173

b=-173/13

b=-13+4/13

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