16(j+1)(j-1)=

Solution for 16(j+1)(j-1)= equation:

Simplifying
16(j + 1)(j + -1) = 0

Reorder the terms:
16(1 + j)(j + -1) = 0

Reorder the terms:
16(1 + j)(-1 + j) = 0

Multiply (1 + j) * (-1 + j)
16(1(-1 + j) + j(-1 + j)) = 0
16((-1 * 1 + j * 1) + j(-1 + j)) = 0
16((-1 + 1j) + j(-1 + j)) = 0
16(-1 + 1j + (-1 * j + j * j)) = 0
16(-1 + 1j + (-1j + j2)) = 0

Combine like terms: 1j + -1j = 0
16(-1 + 0 + j2) = 0
16(-1 + j2) = 0
(-1 * 16 + j2 * 16) = 0
(-16 + 16j2) = 0

Solving
-16 + 16j2 = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 16j2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 16j2 = 0 + 16
16j2 = 0 + 16

Combine like terms: 0 + 16 = 16
16j2 = 16

Divide each side by '16'.
j2 = 1

Simplifying
j2 = 1

Take the square root of each side:
j = {-1, 1}