16(n+1)=3(n-1)-8

Solution for 16(n+1)=3(n-1)-8 equation:

16(n+1)=3(n-1)-8

We move all terms to the left:

16(n+1)-(3(n-1)-8)=0

We multiply parentheses

16n-(3(n-1)-8)+16=0


We calculate terms in parentheses: -(3(n-1)-8), so:

3(n-1)-8

We multiply parentheses

3n-3-8

We add all the numbers together, and all the variables

3n-11

Back to the equation:

-(3n-11)


We get rid of parentheses

16n-3n+11+16=0

We add all the numbers together, and all the variables

13n+27=0

We move all terms containing n to the left, all other terms to the right

13n=-27

n=-27/13

n=-2+1/13