16(n+8)=4(32+4n)

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Solution for 16(n+8)=4(32+4n) equation:


Simplifying
16(n + 8) = 4(32 + 4n)

Reorder the terms:
16(8 + n) = 4(32 + 4n)
(8 * 16 + n * 16) = 4(32 + 4n)
(128 + 16n) = 4(32 + 4n)
128 + 16n = (32 * 4 + 4n * 4)
128 + 16n = (128 + 16n)

Add '-128' to each side of the equation.
128 + -128 + 16n = 128 + -128 + 16n

Combine like terms: 128 + -128 = 0
0 + 16n = 128 + -128 + 16n
16n = 128 + -128 + 16n

Combine like terms: 128 + -128 = 0
16n = 0 + 16n
16n = 16n

Add '-16n' to each side of the equation.
16n + -16n = 16n + -16n

Combine like terms: 16n + -16n = 0
0 = 16n + -16n

Combine like terms: 16n + -16n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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