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16(p-2)7p+4=p
We move all terms to the left:
16(p-2)7p+4-(p)=0
We add all the numbers together, and all the variables
-1p+16(p-2)7p+4=0
We multiply parentheses
112p^2-1p-224p+4=0
We add all the numbers together, and all the variables
112p^2-225p+4=0
a = 112; b = -225; c = +4;
Δ = b2-4ac
Δ = -2252-4·112·4
Δ = 48833
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-\sqrt{48833}}{2*112}=\frac{225-\sqrt{48833}}{224} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+\sqrt{48833}}{2*112}=\frac{225+\sqrt{48833}}{224} $
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