16(r-6)=12(r-9)

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Solution for 16(r-6)=12(r-9) equation: 



16(r-6)=12(r-9)

We move all terms to the left:

16(r-6)-(12(r-9))=0

We multiply parentheses

16r-(12(r-9))-96=0



We calculate terms in parentheses: -(12(r-9)), so:

12(r-9)

We multiply parentheses

12r-108

Back to the equation:

-(12r-108)



We get rid of parentheses

16r-12r+108-96=0

We add all the numbers together, and all the variables

4r+12=0

We move all terms containing r to the left, all other terms to the right

4r=-12

r=-12/4

r=-3

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