16(t+7)=4(4t+28)

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Solution for 16(t+7)=4(4t+28) equation: 



16(t+7)=4(4t+28)

We move all terms to the left:

16(t+7)-(4(4t+28))=0

We multiply parentheses

16t-(4(4t+28))+112=0



We calculate terms in parentheses: -(4(4t+28)), so:

4(4t+28)

We multiply parentheses

16t+112

Back to the equation:

-(16t+112)



We get rid of parentheses

16t-16t-112+112=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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