16(t-2)+5t=7(3t+2)-13

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Solution for 16(t-2)+5t=7(3t+2)-13 equation:


Simplifying
16(t + -2) + 5t = 7(3t + 2) + -13

Reorder the terms:
16(-2 + t) + 5t = 7(3t + 2) + -13
(-2 * 16 + t * 16) + 5t = 7(3t + 2) + -13
(-32 + 16t) + 5t = 7(3t + 2) + -13

Combine like terms: 16t + 5t = 21t
-32 + 21t = 7(3t + 2) + -13

Reorder the terms:
-32 + 21t = 7(2 + 3t) + -13
-32 + 21t = (2 * 7 + 3t * 7) + -13
-32 + 21t = (14 + 21t) + -13

Reorder the terms:
-32 + 21t = 14 + -13 + 21t

Combine like terms: 14 + -13 = 1
-32 + 21t = 1 + 21t

Add '-21t' to each side of the equation.
-32 + 21t + -21t = 1 + 21t + -21t

Combine like terms: 21t + -21t = 0
-32 + 0 = 1 + 21t + -21t
-32 = 1 + 21t + -21t

Combine like terms: 21t + -21t = 0
-32 = 1 + 0
-32 = 1

Solving
-32 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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