16(t-2)+5t=7(3t+5)-10

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Solution for 16(t-2)+5t=7(3t+5)-10 equation: 



16(t-2)+5t=7(3t+5)-10

We move all terms to the left:

16(t-2)+5t-(7(3t+5)-10)=0

We add all the numbers together, and all the variables

5t+16(t-2)-(7(3t+5)-10)=0

We multiply parentheses

5t+16t-(7(3t+5)-10)-32=0



We calculate terms in parentheses: -(7(3t+5)-10), so:

7(3t+5)-10

We multiply parentheses

21t+35-10

We add all the numbers together, and all the variables

21t+25

Back to the equation:

-(21t+25)



We add all the numbers together, and all the variables

21t-(21t+25)-32=0

We get rid of parentheses

21t-21t-25-32=0

We add all the numbers together, and all the variables

-57!=0

There is no solution for this equation

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