16(t-4)+5t=7(3t+2)-12

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Solution for 16(t-4)+5t=7(3t+2)-12 equation:


Simplifying
16(t + -4) + 5t = 7(3t + 2) + -12

Reorder the terms:
16(-4 + t) + 5t = 7(3t + 2) + -12
(-4 * 16 + t * 16) + 5t = 7(3t + 2) + -12
(-64 + 16t) + 5t = 7(3t + 2) + -12

Combine like terms: 16t + 5t = 21t
-64 + 21t = 7(3t + 2) + -12

Reorder the terms:
-64 + 21t = 7(2 + 3t) + -12
-64 + 21t = (2 * 7 + 3t * 7) + -12
-64 + 21t = (14 + 21t) + -12

Reorder the terms:
-64 + 21t = 14 + -12 + 21t

Combine like terms: 14 + -12 = 2
-64 + 21t = 2 + 21t

Add '-21t' to each side of the equation.
-64 + 21t + -21t = 2 + 21t + -21t

Combine like terms: 21t + -21t = 0
-64 + 0 = 2 + 21t + -21t
-64 = 2 + 21t + -21t

Combine like terms: 21t + -21t = 0
-64 = 2 + 0
-64 = 2

Solving
-64 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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