16(v+1)-4v=(3v+1)5

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Solution for 16(v+1)-4v=(3v+1)5 equation: 



16(v+1)-4v=(3v+1)5

We move all terms to the left:

16(v+1)-4v-((3v+1)5)=0

We add all the numbers together, and all the variables

-4v+16(v+1)-((3v+1)5)=0

We multiply parentheses

-4v+16v-((3v+1)5)+16=0



We calculate terms in parentheses: -((3v+1)5), so:

(3v+1)5

We multiply parentheses

15v+5

Back to the equation:

-(15v+5)



We add all the numbers together, and all the variables

12v-(15v+5)+16=0

We get rid of parentheses

12v-15v-5+16=0

We add all the numbers together, and all the variables

-3v+11=0

We move all terms containing v to the left, all other terms to the right

-3v=-11

v=-11/-3

v=3+2/3

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