16(v+1)-4v=4(3v+4)-22

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Solution for 16(v+1)-4v=4(3v+4)-22 equation: 



16(v+1)-4v=4(3v+4)-22

We move all terms to the left:

16(v+1)-4v-(4(3v+4)-22)=0

We add all the numbers together, and all the variables

-4v+16(v+1)-(4(3v+4)-22)=0

We multiply parentheses

-4v+16v-(4(3v+4)-22)+16=0



We calculate terms in parentheses: -(4(3v+4)-22), so:

4(3v+4)-22

We multiply parentheses

12v+16-22

We add all the numbers together, and all the variables

12v-6

Back to the equation:

-(12v-6)



We add all the numbers together, and all the variables

12v-(12v-6)+16=0

We get rid of parentheses

12v-12v+6+16=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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