16(v+2)-4v=3(4v+2)-13

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Solution for 16(v+2)-4v=3(4v+2)-13 equation: 


Simplifying
16(v + 2) + -4v = 3(4v + 2) + -13

Reorder the terms:
16(2 + v) + -4v = 3(4v + 2) + -13
(2 * 16 + v * 16) + -4v = 3(4v + 2) + -13
(32 + 16v) + -4v = 3(4v + 2) + -13

Combine like terms: 16v + -4v = 12v
32 + 12v = 3(4v + 2) + -13

Reorder the terms:
32 + 12v = 3(2 + 4v) + -13
32 + 12v = (2 * 3 + 4v * 3) + -13
32 + 12v = (6 + 12v) + -13

Reorder the terms:
32 + 12v = 6 + -13 + 12v

Combine like terms: 6 + -13 = -7
32 + 12v = -7 + 12v

Add '-12v' to each side of the equation.
32 + 12v + -12v = -7 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 + 0 = -7 + 12v + -12v
32 = -7 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 = -7 + 0
32 = -7

Solving
32 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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