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16(v+2)-4v=3(4v+4)-13
We move all terms to the left:
16(v+2)-4v-(3(4v+4)-13)=0
We add all the numbers together, and all the variables
-4v+16(v+2)-(3(4v+4)-13)=0
We multiply parentheses
-4v+16v-(3(4v+4)-13)+32=0
We calculate terms in parentheses: -(3(4v+4)-13), so:We add all the numbers together, and all the variables
3(4v+4)-13
We multiply parentheses
12v+12-13
We add all the numbers together, and all the variables
12v-1
Back to the equation:
-(12v-1)
12v-(12v-1)+32=0
We get rid of parentheses
12v-12v+1+32=0
We add all the numbers together, and all the variables
33!=0
There is no solution for this equation
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