16(v+2)-4v=4(3v+1)-7

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Solution for 16(v+2)-4v=4(3v+1)-7 equation:


Simplifying
16(v + 2) + -4v = 4(3v + 1) + -7

Reorder the terms:
16(2 + v) + -4v = 4(3v + 1) + -7
(2 * 16 + v * 16) + -4v = 4(3v + 1) + -7
(32 + 16v) + -4v = 4(3v + 1) + -7

Combine like terms: 16v + -4v = 12v
32 + 12v = 4(3v + 1) + -7

Reorder the terms:
32 + 12v = 4(1 + 3v) + -7
32 + 12v = (1 * 4 + 3v * 4) + -7
32 + 12v = (4 + 12v) + -7

Reorder the terms:
32 + 12v = 4 + -7 + 12v

Combine like terms: 4 + -7 = -3
32 + 12v = -3 + 12v

Add '-12v' to each side of the equation.
32 + 12v + -12v = -3 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 + 0 = -3 + 12v + -12v
32 = -3 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 = -3 + 0
32 = -3

Solving
32 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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