16(x+1)=14x+6-x

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Solution for 16(x+1)=14x+6-x equation: 



16(x+1)=14x+6-x

We move all terms to the left:

16(x+1)-(14x+6-x)=0

We add all the numbers together, and all the variables

16(x+1)-(13x+6)=0

We multiply parentheses

16x-(13x+6)+16=0

We get rid of parentheses

16x-13x-6+16=0

We add all the numbers together, and all the variables

3x+10=0

We move all terms containing x to the left, all other terms to the right

3x=-10

x=-10/3

x=-3+1/3

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