16(x+1)=4(4x+1)+12

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Solution for 16(x+1)=4(4x+1)+12 equation: 


Simplifying
16(x + 1) = 4(4x + 1) + 12

Reorder the terms:
16(1 + x) = 4(4x + 1) + 12
(1 * 16 + x * 16) = 4(4x + 1) + 12
(16 + 16x) = 4(4x + 1) + 12

Reorder the terms:
16 + 16x = 4(1 + 4x) + 12
16 + 16x = (1 * 4 + 4x * 4) + 12
16 + 16x = (4 + 16x) + 12

Reorder the terms:
16 + 16x = 4 + 12 + 16x

Combine like terms: 4 + 12 = 16
16 + 16x = 16 + 16x

Add '-16' to each side of the equation.
16 + -16 + 16x = 16 + -16 + 16x

Combine like terms: 16 + -16 = 0
0 + 16x = 16 + -16 + 16x
16x = 16 + -16 + 16x

Combine like terms: 16 + -16 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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