16(x+1/2)(x+1/2)=1

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Solution for 16(x+1/2)(x+1/2)=1 equation: 


x in (-oo:+oo)

16*(x+1/2)*(x+1/2) = 1 // - 1

16*(x+1/2)*(x+1/2)-1 = 0

16*(x+1/2)^2-1 = 0

16*(x+1/2)^2-1 = 0

16*x^2+16*x+3 = 0

16*x^2+16*x+3 = 0

16*x^2+16*x+3 = 0

DELTA = 16^2-(3*4*16)

DELTA = 64

DELTA > 0

x = (64^(1/2)-16)/(2*16) or x = (-64^(1/2)-16)/(2*16)

x = -1/4 or x = -3/4

(x+3/4)*(x+1/4) = 0

(x+3/4)*(x+1/4) = 0

( x+1/4 )

x+1/4 = 0 // - 1/4

x = -1/4

( x+3/4 )

x+3/4 = 0 // - 3/4

x = -3/4

x in { -1/4, -3/4 }

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