16(x+2)=2(x-4)

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Solution for 16(x+2)=2(x-4) equation: 



16(x+2)=2(x-4)

We move all terms to the left:

16(x+2)-(2(x-4))=0

We multiply parentheses

16x-(2(x-4))+32=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

16x-2x+8+32=0

We add all the numbers together, and all the variables

14x+40=0

We move all terms containing x to the left, all other terms to the right

14x=-40

x=-40/14

x=-2+6/7

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