16(x+2)=4(4x+1)+28

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Solution for 16(x+2)=4(4x+1)+28 equation: 


Simplifying
16(x + 2) = 4(4x + 1) + 28

Reorder the terms:
16(2 + x) = 4(4x + 1) + 28
(2 * 16 + x * 16) = 4(4x + 1) + 28
(32 + 16x) = 4(4x + 1) + 28

Reorder the terms:
32 + 16x = 4(1 + 4x) + 28
32 + 16x = (1 * 4 + 4x * 4) + 28
32 + 16x = (4 + 16x) + 28

Reorder the terms:
32 + 16x = 4 + 28 + 16x

Combine like terms: 4 + 28 = 32
32 + 16x = 32 + 16x

Add '-32' to each side of the equation.
32 + -32 + 16x = 32 + -32 + 16x

Combine like terms: 32 + -32 = 0
0 + 16x = 32 + -32 + 16x
16x = 32 + -32 + 16x

Combine like terms: 32 + -32 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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