16(x+4)=4(4x+2)+56

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Solution for 16(x+4)=4(4x+2)+56 equation:


Simplifying
16(x + 4) = 4(4x + 2) + 56

Reorder the terms:
16(4 + x) = 4(4x + 2) + 56
(4 * 16 + x * 16) = 4(4x + 2) + 56
(64 + 16x) = 4(4x + 2) + 56

Reorder the terms:
64 + 16x = 4(2 + 4x) + 56
64 + 16x = (2 * 4 + 4x * 4) + 56
64 + 16x = (8 + 16x) + 56

Reorder the terms:
64 + 16x = 8 + 56 + 16x

Combine like terms: 8 + 56 = 64
64 + 16x = 64 + 16x

Add '-64' to each side of the equation.
64 + -64 + 16x = 64 + -64 + 16x

Combine like terms: 64 + -64 = 0
0 + 16x = 64 + -64 + 16x
16x = 64 + -64 + 16x

Combine like terms: 64 + -64 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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