16(x+5)=4(4x+2)+72

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Solution for 16(x+5)=4(4x+2)+72 equation: 



16(x+5)=4(4x+2)+72

We move all terms to the left:

16(x+5)-(4(4x+2)+72)=0

We multiply parentheses

16x-(4(4x+2)+72)+80=0



We calculate terms in parentheses: -(4(4x+2)+72), so:

4(4x+2)+72

We multiply parentheses

16x+8+72

We add all the numbers together, and all the variables

16x+80

Back to the equation:

-(16x+80)



We get rid of parentheses

16x-16x-80+80=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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