16(x-2)+34=7(4+x)

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Solution for 16(x-2)+34=7(4+x) equation: 



16(x-2)+34=7(4+x)

We move all terms to the left:

16(x-2)+34-(7(4+x))=0

We add all the numbers together, and all the variables

16(x-2)-(7(x+4))+34=0

We multiply parentheses

16x-(7(x+4))-32+34=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We add all the numbers together, and all the variables

16x-(7x+28)+2=0

We get rid of parentheses

16x-7x-28+2=0

We add all the numbers together, and all the variables

9x-26=0

We move all terms containing x to the left, all other terms to the right

9x=26

x=26/9

x=2+8/9

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