16(x-3)+10=2(3x-4)

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Solution for 16(x-3)+10=2(3x-4) equation: 



16(x-3)+10=2(3x-4)

We move all terms to the left:

16(x-3)+10-(2(3x-4))=0

We multiply parentheses

16x-(2(3x-4))-48+10=0



We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We add all the numbers together, and all the variables

16x-(6x-8)-38=0

We get rid of parentheses

16x-6x+8-38=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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