16(x-3)=12x+4x-12*4

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Solution for 16(x-3)=12x+4x-12*4 equation: 


Simplifying
16(x + -3) = 12x + 4x + -12 * 4

Reorder the terms:
16(-3 + x) = 12x + 4x + -12 * 4
(-3 * 16 + x * 16) = 12x + 4x + -12 * 4
(-48 + 16x) = 12x + 4x + -12 * 4

Multiply -12 * 4
-48 + 16x = 12x + 4x + -48

Reorder the terms:
-48 + 16x = -48 + 12x + 4x

Combine like terms: 12x + 4x = 16x
-48 + 16x = -48 + 16x

Add '48' to each side of the equation.
-48 + 48 + 16x = -48 + 48 + 16x

Combine like terms: -48 + 48 = 0
0 + 16x = -48 + 48 + 16x
16x = -48 + 48 + 16x

Combine like terms: -48 + 48 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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