16(y+1)=3(y-11)-42

Solution for 16(y+1)=3(y-11)-42 equation:

16(y+1)=3(y-11)-42

We move all terms to the left:

16(y+1)-(3(y-11)-42)=0

We multiply parentheses

16y-(3(y-11)-42)+16=0


We calculate terms in parentheses: -(3(y-11)-42), so:

3(y-11)-42

We multiply parentheses

3y-33-42

We add all the numbers together, and all the variables

3y-75

Back to the equation:

-(3y-75)


We get rid of parentheses

16y-3y+75+16=0

We add all the numbers together, and all the variables

13y+91=0

We move all terms containing y to the left, all other terms to the right

13y=-91

y=-91/13

y=-7