16(z+2)=23

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Solution for 16(z+2)=23 equation: 



16(z+2)=23

We move all terms to the left:

16(z+2)-(23)=0

We multiply parentheses

16z+32-23=0

We add all the numbers together, and all the variables

16z+9=0

We move all terms containing z to the left, all other terms to the right

16z=-9

z=-9/16

z=-9/16

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