16(z+3)+5(4z-6)=3(z-5)+8

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Solution for 16(z+3)+5(4z-6)=3(z-5)+8 equation: 



16(z+3)+5(4z-6)=3(z-5)+8

We move all terms to the left:

16(z+3)+5(4z-6)-(3(z-5)+8)=0

We multiply parentheses

16z+20z-(3(z-5)+8)+48-30=0



We calculate terms in parentheses: -(3(z-5)+8), so:

3(z-5)+8

We multiply parentheses

3z-15+8

We add all the numbers together, and all the variables

3z-7

Back to the equation:

-(3z-7)



We add all the numbers together, and all the variables

36z-(3z-7)+18=0

We get rid of parentheses

36z-3z+7+18=0

We add all the numbers together, and all the variables

33z+25=0

We move all terms containing z to the left, all other terms to the right

33z=-25

z=-25/33

z=-25/33

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