16(z+3)=4(z+9)+12z+12

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Solution for 16(z+3)=4(z+9)+12z+12 equation: 


Simplifying
16(z + 3) = 4(z + 9) + 12z + 12

Reorder the terms:
16(3 + z) = 4(z + 9) + 12z + 12
(3 * 16 + z * 16) = 4(z + 9) + 12z + 12
(48 + 16z) = 4(z + 9) + 12z + 12

Reorder the terms:
48 + 16z = 4(9 + z) + 12z + 12
48 + 16z = (9 * 4 + z * 4) + 12z + 12
48 + 16z = (36 + 4z) + 12z + 12

Reorder the terms:
48 + 16z = 36 + 12 + 4z + 12z

Combine like terms: 36 + 12 = 48
48 + 16z = 48 + 4z + 12z

Combine like terms: 4z + 12z = 16z
48 + 16z = 48 + 16z

Add '-48' to each side of the equation.
48 + -48 + 16z = 48 + -48 + 16z

Combine like terms: 48 + -48 = 0
0 + 16z = 48 + -48 + 16z
16z = 48 + -48 + 16z

Combine like terms: 48 + -48 = 0
16z = 0 + 16z
16z = 16z

Add '-16z' to each side of the equation.
16z + -16z = 16z + -16z

Combine like terms: 16z + -16z = 0
0 = 16z + -16z

Combine like terms: 16z + -16z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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