16(z+3)=4(z-9)

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Solution for 16(z+3)=4(z-9) equation:


Simplifying
16(z + 3) = 4(z + -9)

Reorder the terms:
16(3 + z) = 4(z + -9)
(3 * 16 + z * 16) = 4(z + -9)
(48 + 16z) = 4(z + -9)

Reorder the terms:
48 + 16z = 4(-9 + z)
48 + 16z = (-9 * 4 + z * 4)
48 + 16z = (-36 + 4z)

Solving
48 + 16z = -36 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
48 + 16z + -4z = -36 + 4z + -4z

Combine like terms: 16z + -4z = 12z
48 + 12z = -36 + 4z + -4z

Combine like terms: 4z + -4z = 0
48 + 12z = -36 + 0
48 + 12z = -36

Add '-48' to each side of the equation.
48 + -48 + 12z = -36 + -48

Combine like terms: 48 + -48 = 0
0 + 12z = -36 + -48
12z = -36 + -48

Combine like terms: -36 + -48 = -84
12z = -84

Divide each side by '12'.
z = -7

Simplifying
z = -7

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