16(z+3)=4)z+9

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Solution for 16(z+3)=4)z+9 equation: 



16(z+3)=4)z+9

We move all terms to the left:

16(z+3)-(4)z+9)=0

We add all the numbers together, and all the variables

-4z+16(z+3)=0

We multiply parentheses

-4z+16z+48=0

We add all the numbers together, and all the variables

12z+48=0

We move all terms containing z to the left, all other terms to the right

12z=-48

z=-48/12

z=-4

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