16(z-3)=4(z-5)

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Solution for 16(z-3)=4(z-5) equation: 



16(z-3)=4(z-5)

We move all terms to the left:

16(z-3)-(4(z-5))=0

We multiply parentheses

16z-(4(z-5))-48=0



We calculate terms in parentheses: -(4(z-5)), so:

4(z-5)

We multiply parentheses

4z-20

Back to the equation:

-(4z-20)



We get rid of parentheses

16z-4z+20-48=0

We add all the numbers together, and all the variables

12z-28=0

We move all terms containing z to the left, all other terms to the right

12z=28

z=28/12

z=2+1/3

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