16+((x-4)x(x+4))=0

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Solution for 16+((x-4)x(x+4))=0 equation: 


Simplifying
16 + ((x + -4) * x(x + 4)) = 0

Reorder the terms:
16 + ((-4 + x) * x(x + 4)) = 0

Reorder the terms:
16 + ((-4 + x) * x(4 + x)) = 0

Reorder the terms for easier multiplication:
16 + (x(-4 + x)(4 + x)) = 0

Multiply (-4 + x) * (4 + x)
16 + (x(-4(4 + x) + x(4 + x))) = 0
16 + (x((4 * -4 + x * -4) + x(4 + x))) = 0
16 + (x((-16 + -4x) + x(4 + x))) = 0
16 + (x(-16 + -4x + (4 * x + x * x))) = 0
16 + (x(-16 + -4x + (4x + x2))) = 0

Combine like terms: -4x + 4x = 0
16 + (x(-16 + 0 + x2)) = 0
16 + (x(-16 + x2)) = 0
16 + ((-16 * x + x2 * x)) = 0
16 + ((-16x + x3)) = 0
16 + (-16x + x3) = 0

Remove parenthesis around (-16x + x3)
16 + -16x + x3 = 0

Solving
16 + -16x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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