16+1/4x+2=9x+18

Solution for 16+1/4x+2=9x+18 equation:

16+1/4x+2=9x+18

We move all terms to the left:

16+1/4x+2-(9x+18)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(9x+18)+18=0

We get rid of parentheses

1/4x-9x-18+18=0

We multiply all the terms by the denominator


-9x*4x-18*4x+18*4x+1=0

Wy multiply elements

-36x^2-72x+72x+1=0

We add all the numbers together, and all the variables

-36x^2+1=0

a = -36; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-36)·1
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-36}=\frac{-12}{-72}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-36}=\frac{12}{-72}
=-1/6
$