16+12=-3z+7z

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Solution for 16+12=-3z+7z equation: 



16+12=-3z+7z

We move all terms to the left:

16+12-(-3z+7z)=0

We add all the numbers together, and all the variables

-(+4z)+16+12=0

We add all the numbers together, and all the variables

-(+4z)+28=0

We get rid of parentheses

-4z+28=0

We move all terms containing z to the left, all other terms to the right

-4z=-28

z=-28/-4

z=+7

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