16+2(4x-4)=8-4(2x+1)

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Solution for 16+2(4x-4)=8-4(2x+1) equation:



16+2(4x-4)=8-4(2x+1)
We move all terms to the left:
16+2(4x-4)-(8-4(2x+1))=0
We multiply parentheses
8x-(8-4(2x+1))-8+16=0
We calculate terms in parentheses: -(8-4(2x+1)), so:
8-4(2x+1)
determiningTheFunctionDomain -4(2x+1)+8
We multiply parentheses
-8x-4+8
We add all the numbers together, and all the variables
-8x+4
Back to the equation:
-(-8x+4)
We add all the numbers together, and all the variables
8x-(-8x+4)+8=0
We get rid of parentheses
8x+8x-4+8=0
We add all the numbers together, and all the variables
16x+4=0
We move all terms containing x to the left, all other terms to the right
16x=-4
x=-4/16
x=-1/4

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