16+2j+j-10=11j+13-8j-7

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Solution for 16+2j+j-10=11j+13-8j-7 equation:



16+2j+j-10=11j+13-8j-7
We move all terms to the left:
16+2j+j-10-(11j+13-8j-7)=0
We add all the numbers together, and all the variables
2j+j-(3j+6)+16-10=0
We add all the numbers together, and all the variables
3j-(3j+6)+6=0
We get rid of parentheses
3j-3j-6+6=0
We add all the numbers together, and all the variables
=0
j=0/1
j=0

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