16+2v=4(4+6v)+8v

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Solution for 16+2v=4(4+6v)+8v equation: 



16+2v=4(4+6v)+8v

We move all terms to the left:

16+2v-(4(4+6v)+8v)=0

We add all the numbers together, and all the variables

2v-(4(6v+4)+8v)+16=0



We calculate terms in parentheses: -(4(6v+4)+8v), so:

4(6v+4)+8v

We add all the numbers together, and all the variables

8v+4(6v+4)

We multiply parentheses

8v+24v+16

We add all the numbers together, and all the variables

32v+16

Back to the equation:

-(32v+16)



We get rid of parentheses

2v-32v-16+16=0

We add all the numbers together, and all the variables

-30v=0

v=0/-30

v=0

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