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16+2x=2(x+1)+8
We move all terms to the left:
16+2x-(2(x+1)+8)=0
We calculate terms in parentheses: -(2(x+1)+8), so:We get rid of parentheses
2(x+1)+8
We multiply parentheses
2x+2+8
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
2x-2x-10+16=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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